"HOLD KEY"(keyboard) logic

Coding Python Support
1 
import bge


def main():

    cont = bge.logic.getCurrentController()
    jumpBAR = cont.owner

    keypress = bge.logic.keyboard.events
    JUST_ACTIVE = bge.logic.KX_INPUT_ACTIVE
    JUST_RELEASED = bge.logic.KX_INPUT_JUST_RELEASED
    JUST_ACTIVATED = bge.logic.KX_INPUT_JUST_ACTIVATED

    if (jumpBAR['animJUMP'] == 0):
        jumpBAR.visible = False
        
    if keypress[bge.events.SPACEKEY] == JUST_ACTIVE:
        if not keypress[bge.events.SPACEKEY] == JUST_RELEASED:
            jumpBAR['GcurJUMP'] = jumpBAR['curJUMP']
            jumpBAR['curJUMP'] = jumpBAR['curJUMP'] + 2      
            percHP = jumpBAR['curJUMP'] / jumpBAR['maxJUMP'] * 100
            GpercHP = jumpBAR['GcurJUMP'] / jumpBAR['maxJUMP'] * 100
            jumpBAR['animJUMP'] = percHP * 5
            jumpBAR['GanimJUMP'] = GpercHP * 5
            jumpBAR.visible = True
            jumpBAR.playAction("Bar-Jump-Move", jumpBAR['GanimJUMP'], jumpBAR['animJUMP'], play_mode=bge.logic.KX_ACTION_MODE_PLAY, speed = 10.0)
            if jumpBAR['curJUMP'] > jumpBAR['maxJUMP']:
                jumpBAR['curJUMP'] = 0
        print("I only want to go here once the key is released")

main()

I am trying to charge / count a variable while the SPACEKEY is held. The problem is, ever tick the JUST_ACTIVE logic finishes going to the print line listed at the bottom every cycle. How can I start routine until a key is released and not break out of it until then? Thank you.

2

if there is a different way to do it w/ code, im all ears

3

if keypress[bge.events.SPACEKEY] == JUST_ACTIVE:
# DO STUFF WHILE KEY BEING HELD

if keypress[bge.events.SPACEKEY] == JUST_RELEASED:
# DO STUFF WHEN KEY IS RELEASED

It was a matter of pulling the indent for JUST_RELEASED outside of the JUST_ACTIVE loop. Every tick the key will be active, so put it to “JUST RELEASED” (which isn’t active) and it’ll work. Duh.