I’m using (y = x**2.7 + 20) in part of my code right now. I need something steeper but at the same time I need (y = 20000 when x = 40), and (y = 20 when x = 0).
what about y = x**4 / 128 + 20
perfect, thanks!
I’m using (y = x**2.7 + 20) in part of my code right now. I need something steeper but at the same time I need (y = 20000 when x = 40), and (y = 20 when x = 0).
what about y = x**4 / 128 + 20
perfect, thanks!