If statement for clipboard number that comes as a string?

Coding Python Support
1

Hello!

I’m trying to take clipboard value and, if it’s a number, let my code use it.

But I’m getting stuck over initial if statement, failing at decision, if the clipboard string is a number or not.

Would anyone know how to get this to work?

Thank you!

            tempintvalue = int(bpy.context.window_manager.clipboard)
                if tempintvalue is int:
                    self.message(f'test1')
                    outcome_value = int(bpy.context.window_manager.clipboard)
                else:
                    self.message(f'test2')
                    outcome_value = 0

The code above gives me following error

    tempintvalue = int(bpy.context.window_manager.clipboard)
ValueError: invalid literal for int() with base 10: 'tfdfew'

“tfdfew” is a random clipboard value that should be ignored in this case

2

This is the wrong approach. Your if statement is pointless, because it will only ever return true. Int(n) is int? Is, by definition, always true.

Instead, replace everything with this:


tempintvalue=bpy.context.window_manager.clipboard

if isinstance(tempintvalue, int): 
    do something 
else: 
    do something else
3

I see.

I tried your snippet, but it keeps ignoring any numeral value every time, unfortunately.

4

You could always do it the “wrong” way:

tempintvalue=bpy.context.window_manager.clipboard

def getInt(t):
try: 
    return int(t)
except:
    return False

b = getInt(tempintvalue)
if b != False: 
    do something with the int
else:
    do something with the not-int