dims = Array[22,22,22]
And second an array/list of floats with a value between 0 and 1… this list is has a value for every possible position within the dimensions of 22,22,22 (so… 22 * 22 * 22 = 10648 values).
So a simple example of a minimal shape would be dimensions of 3 * 3 * 3
This would be dims = Array[3,3,3]
And the io array would be io = Array[1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,1,1,1,1,1,1,1,1,1,1,1,1] (27 values and in this case only the middle one is ‘inside’
Thanks for looking into this. Please consider what your fee is to get this working! Feel free to e-mail me as well.