nil value for multiply

Coding Python Support
1

i got asimple equaton and get a value of 0?

genr = 10.0

print ‘genr*(2/3)=’, genr*(2/3),‘genr =’,genr

and this get me genr*(2/3), =0 ?

how can i correct this so it works?

Thanks

2

Hi,

Looks like you’re using integers in your division. Try

genr = 10.0
print 'genr*(2/3)=', genr*(2/3.0),'genr =',genr
3

so as soon as you put an expression with integer the rest of the equation is evalutated as integer!

hum ?

Thanks i’ll change it to real number

4

Hi,

If you present an expression containing only integers, the result will be returned as an integer. If you need greater precision, you should include a higher precision value in the expression (e.g. a float). It seems a bit strange, but there are good reasons for it to work this way.

5

Although I think I read that for Python 3.0, it does an automatic conversion to float. In older versions there’s:


from __future__ import division

if its really necessary it operate as it would mathematically…

6

you put that at the beginning of the main i guess

and it will work with the python 2.6 with 2.49a

i hope 2.5 will be with python 3

it might be easier to program that way

now i still have to settled the other problem with Nesh and ob data
but htat’s part of another thread anyway

Thanks guys